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-12x^2=-12x+3
We move all terms to the left:
-12x^2-(-12x+3)=0
We get rid of parentheses
-12x^2+12x-3=0
a = -12; b = 12; c = -3;
Δ = b2-4ac
Δ = 122-4·(-12)·(-3)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-12}{-24}=1/2$
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